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EAMCET Medical EAMCET Medical Solved Paper-2008

  • question_answer
    \[\text{100}\,\text{c}{{\text{m}}^{\text{3}}}\]of \[\text{0}\text{.1 M HCl}\] and \[\text{100}\,\text{c}{{\text{m}}^{\text{3}}}\] of 0.1 M \[\text{NaOH}\] solutions are mixed in a calorimeter. If the heat liberated is "Q" kcal, the heat of neutralisation \[\text{( }\!\!\Delta\!\!\text{ H)}\] (in kcal) of \[\text{HCl(aq)}\] and \[\text{NaOH(aq)}\] is

    A)  \[-10Q\]                             

    B)  \[-100Q\]

    C)  \[-1000Q\]                        

    D)  \[Q\]

    Correct Answer: B

    Solution :

                     Number of moles of \[\text{HCl}=100\times 0.1=10\] Number of moles of \[\text{NaOH =100}\times \text{0}\text{.1=10}\] \[NaOH+HCl\xrightarrow{{}}NaCl+{{H}_{2}}O\] \[\because \] when 1 mole of \[\text{NaOH}\] is neutralised by mole of \[\text{HCl,}\] Then, the heat liberated is = Q kcal or                 \[\Delta H=-Q\,\text{kcal}\] \[\therefore \] 10 moles of \[\text{NaOH}\] are neutralised by 10 moles of \[\text{HCl,}\] Heat liberated, \[\Delta H=-10\times 10\times Q\,\text{kcal}\]                                 \[=-100Q\,\text{kcal}\]


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