A) \[CaOC{{l}_{2}}\]
B) \[Ca{{(C1{{O}_{3}})}_{2}}\]
C) \[Ca{{(OH)}_{2}}\]
D) \[Ca{{(Cl{{O}_{2}})}_{2}}\]
Correct Answer: B
Solution :
Calcium hydroxide or slaked lime \[[Ca{{(OH)}_{2}}]\] reacts with \[\text{C}{{\text{l}}_{\text{2}}}\]to give bleaching powder, \[\text{CaOC}{{\text{l}}_{\text{2}}}\text{.}\] Bleaching powder on auto-oxidation gives calcium chlorate, \[\text{ }\!\![\!\!\text{ Ca(Cl}{{\text{O}}_{3}}{{\text{)}}_{2}}\text{ }\!\!]\!\!\text{ }\text{.}\] \[\underset{dry}{\mathop{Ca{{(OH)}_{2}}}}\,\xrightarrow[-{{H}_{2}}O]{C{{l}_{2}}}\underset{\begin{smallmatrix} bleaching\,powder \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(A) \end{smallmatrix}}{\mathop{CaOC{{l}_{2}}}}\,\] \[\xrightarrow{Auto-oxidation}5CaC{{l}_{2}}+\underset{\begin{smallmatrix} \text{calcium}\,\text{chlorate} \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(B) \end{smallmatrix}}{\mathop{Ca{{(Cl{{O}_{3}})}_{2}}}}\,\]
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