A) \[[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}:{{K}_{3}}[Fe{{(CN)}_{6}}]\]
B) \[[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}};[Cr{{({{H}_{2}}O)}_{6}}]C{{l}_{3}}]\]
C) \[[Fe{{(CO)}_{5}}];{{K}_{4}}[Fe{{(CN)}_{6}}]\]
D) \[[Fe{{(CO)}_{5}}];{{K}_{3}}[Fe{{(CN)}_{6}}]\]
Correct Answer: C
Solution :
EAN = At. no. of central metal ion - (oxidation state of central metal) \[+(C.N.\times 2)\]where, EAN = Effective atomic number. In \[[Fe{{(CO)}_{5}}],EAN\]for Fe \[EAN=26-0+(5\times 2)\] \[=26+10=36\] In \[{{K}_{4}}[Fe{{(CN)}_{6}}],EAN\]of Fe \[=26-2+(6\times 2)\] \[=26-2+12\] \[=36\] Hence, in \[[Fe{{(CO)}_{5}}]\] and \[{{K}_{4}}[Fe{{(CN)}_{6}}]\]the EAN for central metal ie, Fe is 36.
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