2. Solved Papers
  3. EAMCET Medical

EAMCET Medical EAMCET Medical Solved Paper-2008

  • question_answer
    5 L aqueous solution is kept in the presence of oxygen and suitable micro-organism for five days at \[\text{20}{{\,}^{\text{o}}}\text{C}\text{.}\] If the \[{{\text{O}}_{2}}\] consumed is 0.2 g, the BOD value of the sample is

    A)  4ppm                                  

    B)  \[0.4,mg\,{{L}^{-1}}\]

    C)  40ppm                                

    D)  \[20\,\text{mg}\,{{\text{L}}^{-1}}\]

    Correct Answer: C

    Solution :

                     Water pollution is measured by BOD (biochemical oxygen demand) and BOD is a   standardised measurement of the amount of oxygen required by microorganism to cause the decomposition of organic matter over a period of 5 days at \[\text{20}{{\,}^{\text{o}}}\text{C}\text{.}\] \[\text{BOD }\,\text{=}\frac{\text{weight}\,\text{of oxygen(in mg)}}{\text{volume of water sample (in L)}}\] Given, Weight of oxygen = 0.2 g = 200 mg         Volume of solution = 5 L \[BOD=\frac{200}{5}mg/L\] \[=40\,mg/L=40\,ppm\]


You need to login to perform this action.
You will be redirected in 3 sec spinner