A) I
B) I/2
C) I/4
D) \[\frac{I}{\sqrt{2}}\]
Correct Answer: C
Solution :
From \[I={{({{a}_{1}}+{{a}_{2}})}^{2}}\] \[={{(a+a)}^{2}}\] \[=4{{a}^{2}}\] When one slit is closed \[I={{a}^{2}}\] \[\therefore \] \[\frac{I}{I}=\frac{4{{a}^{2}}}{{{a}^{2}}}=4\] or \[I=\frac{I}{4}\]You need to login to perform this action.
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