A) 0.4 atm
B) 0.3 atm
C) 0.2 atm
D) 0.1 atm
Correct Answer: A
Solution :
Given, Total pressure = 1 atm Moles of oxygen =0.2 Moles of nitrogen =0.4 Moles of \[N{{H}_{3}}=0.1\] Moles of He =0.3 Total number of moles = 0.2 + 0.4 + 0.1 4- 0.3 =1.0 Partial pressure of nitrogen = total pressure \[\times \] mole fraction of nitrogen moles of nitrogen \[\text{= 1}\,\text{atm }\!\!\times\!\!\text{ }\frac{\text{moles of nitrogen}}{\text{total number of moles}}\] \[=1\times \frac{0.4}{1}=0.4\,\,\text{atm}\]You need to login to perform this action.
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