A) ,
B) (B,)
C) ,
D) ,
Correct Answer: C
Solution :
According to Bronsted-Lowry, acids are the substance which can donate a proton while bases are the substance which can accept a proton. A base after gaining a proton \[({{H}^{+}})\] gives conjugated acid. \[\underset{acid}{\mathop{{{[Al{{({{H}_{2}}O)}_{6}}]}^{3+}}}}\,+\underset{\begin{smallmatrix} (B) \\ base \end{smallmatrix}}{\mathop{HCO_{3}^{-}}}\,\rightleftharpoons \]\[\underset{\begin{smallmatrix} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C \\ conjugate\,base \end{smallmatrix}}{\mathop{{{[Al{{({{H}_{2}}O)}_{5}}(O{{H}^{-}})]}^{2+}}}}\,+\underset{\begin{smallmatrix} \,\,\,\,\,\,\,\,\,\,\,\,\,(D) \\ conjugate\,acid \end{smallmatrix}}{\mathop{{{H}_{2}}C{{O}_{3}}}}\,\] Hence, in the above reaction A and D are the acids.You need to login to perform this action.
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