A) I, II
B) II, III
C) III,IV
D) II, IV
Correct Answer: D
Solution :
(i) \[2C{{H}_{3}}COO\underline{H}+2Na\xrightarrow{{}}2C{{H}_{3}}COONa+{{H}_{2}}\] (ii) \[C{{H}_{3}}COO\underline{H}+PC{{l}_{5}}\xrightarrow{{}}C{{H}_{3}}COCl+POC{{l}_{3}}+HCl\] (iii) \[C{{H}_{3}}COO\underline{H}+NaHC{{O}_{3}}\xrightarrow{{}}C{{H}_{3}}COONa\]\[+{{H}_{2}}O+C{{O}_{2}}\uparrow \] (iv) \[C{{H}_{3}}CO\underline{OH}+HO{{C}_{2}}{{H}_{5}}\xrightarrow{{}}\]\[\underset{\text{ester}}{\mathop{C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}}}\,+{{H}_{2}}O\] It is clear from the above reactions that Eq. (II) and (IV) involve C?OH bond.You need to login to perform this action.
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