A simple pendulum is executing SHM with a period of 6 s between two extreme positions B and C about a point O. If the length of the arc BC is 10 cm, how long will the pendulum take the move from position C to a position D towards O exactly midway between C and O?
A) 0.5 s
B) 1 s
C) 1-5 s
D) 3 s
Correct Answer:
C
Solution :
Particle is executing SHM. Since, T = 6 s Obviously, time taken from O to C will be 3 s. So, time taken from C to\[D=\frac{T}{4}=\frac{6}{4}=1.5\,s\]