2. Solved Papers
  3. EAMCET Medical

EAMCET Medical EAMCET Medical Solved Paper-2009

  • question_answer
    Four light sources produce the following four waves: (i) \[{{y}_{1}}=a\,\sin \,\left( \omega t\,+\,{{\phi }_{1}} \right)\] (ii) \[{{y}_{2}}=a\,\sin \,2\omega t\] (iii) \[{{y}_{3}}={{a}^{}}\,\sin \,(\omega t+{{\phi }_{2}})\] (iv) \[{{y}_{4}}={{a}^{}}\,\sin \,(3\omega t+\phi )\] Superposition of which two waves gives rise to interference?

    A)  (i) and (ii)                           

    B)  (ii) and (iii)

    C)  (i) and (iii)                          

    D)  (iii) and (iv)

    Correct Answer: C

    Solution :

     For interference phenomenon, we know that when two waves of equal frequency  propagate in same medium and same direction, then interference phenomenon takes place. Here waves,  \[{{y}_{1}}=a\sin (\omega t+\text{o}{{\text{ }\!\!|\!\!\text{ }}_{1}})\]\[{{y}_{3}}=a\sin (\omega t+\text{o}{{\text{ }\!\!|\!\!\text{ }}_{2}})\]have equal frequency, hence they will produce interference.


You need to login to perform this action.
You will be redirected in 3 sec spinner