EAMCET Medical EAMCET Medical Solved Paper-2009

  • question_answer
    The critical angle of a transparent crystal is 45°. Then its polarizing angle is

    A)  \[\theta ={{\tan }^{-1}}\left( \sqrt{2} \right)\]                  

    B)  \[\theta =si{{n}^{-1}}\left( \sqrt{2} \right)\]

    C)   \[\theta ={{\cos }^{-1}}\left( \frac{1}{\sqrt{2}} \right)\]                               

    D)  \[\theta ={{\cot }^{-1}}\left( \sqrt{2} \right)\]

    Correct Answer: A

    Solution :

     Given that, C = 45° For total internal reflection, \[\mu =\frac{1}{\sin C}=\frac{1}{\sin {{45}^{o}}}\]                 or            \[\mu =\sqrt{2}\] But         \[\mu =\tan \theta \](by Brewsters law) \[\therefore \]  \[\theta ={{\tan }^{-1}}\mu \] or            \[\theta ={{\tan }^{-1}}(\sqrt{2})\]


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