A) \[\frac{M}{2\pi }\]
B) \[\frac{M}{\pi }\]
C) \[\frac{M\left( 2+\pi \right)}{2\pi }\]
D) \[\frac{M\pi }{2+\pi }\]
Correct Answer: C
Solution :
\[M=(m\times L)\]where m = pole strength of magnetic dipole, Magnetic dipole moment of A. \[M=m\times (2R)\] Since, \[R\times \pi =\frac{L}{2}\] or \[2R=\frac{L}{\pi }\] \[\therefore \] \[M=\left( \frac{mL}{\pi } \right)\] or \[M=\left( \frac{M}{\pi } \right)\] The magnetic moment of B \[M\,=m\times \frac{L}{2}\] \[M\,=\left( \frac{M}{2} \right)\] Hence, resultant magnetic moment \[{{M}_{R}}=M+M\,=\frac{M}{\pi }+\frac{M}{2}=M\left( \frac{2+\pi }{2\pi } \right)\]You need to login to perform this action.
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