| List I | List II | ||
| A | \[C{{H}_{4}}\to HCN\] | I | \[N{{H}_{3}}|A{{l}_{2}}{{O}_{3}}|\]\[1000{{\,}^{o}}C\] |
| B | \[{{C}_{2}}{{H}_{2}}\to C{{H}_{3}}CHO\] | II | \[450{{\,}^{o}}C,\]heating |
| C | \[{{C}_{2}}{{H}_{4}}\to {{C}_{2}}{{H}_{5}}OH\] | III | \[40%{{H}_{2}}\]\[S{{O}_{4}},1%\]\[HgS{{O}_{4}},6{{\,}^{o}}C\] |
| D | \[{{C}_{2}}{{H}_{6}}\to {{C}_{2}}{{H}_{4}}\] | IV | Conc. \[{{H}_{2}}S{{O}_{4}},\]\[{{H}_{2}}O,80{{\,}^{o}}C\] |
| V | Na, dry ether, \[\Delta \] |
A) A-I B-III C-IV D-II
B) A-I B-II C-IV D-III
C) A-I B-IV C-III D-II
D) A-V B-I C-IV D-III
Correct Answer: A
Solution :
\[C{{H}_{4}}+N{{H}_{3}}\xrightarrow[A{{l}_{2}}{{O}_{3}}]{1000{{\,}^{o}}C}HCN+3{{H}_{2}}\uparrow \] \[CH\equiv CH+{{H}_{2}}O\xrightarrow[6{{\,}^{o}}C]{40%\,{{H}_{2}}S{{O}_{4}},1%HgS{{O}_{4}}}\] \[C{{H}_{3}}CHO\] \[{{C}_{2}}{{H}_{4}}\xrightarrow{Conc.{{H}_{2}}S{{O}_{4}}}{{C}_{2}}{{H}_{5}}HS{{O}_{4}}\xrightarrow[\begin{smallmatrix}+{{H}_{2}}O \\ -{{H}_{2}}S{{O}_{4}} \end{smallmatrix}]{80{{\,}^{o}}C}\]\[{{C}_{2}}{{H}_{5}}OH\] \[{{C}_{2}}{{H}_{6}}\xrightarrow[450{{\,}^{o}}C]{\Delta }{{C}_{2}}{{H}_{4}}+{{H}_{2}}\]
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