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EAMCET Medical EAMCET Medical Solved Paper-2009

  • question_answer
    The ratio of moles of hydrogen produced when two moles of aluminium react with excess \[\text{HCl}\] and \[\text{NaOH}\] separately is

    A)  1:1                                        

    B)  1: 2

    C)  2:1                                        

    D)  3:2

    Correct Answer: A

    Solution :

                     \[2Al+6HCl\xrightarrow{{}}2AlC{{l}_{3}}+3{{H}_{2}}\uparrow \] \[2Al+2NaOH+2{{H}_{2}}O\xrightarrow{{}}2NaAl{{O}_{2}}+3{{H}_{2}}\uparrow \]Hence, ratio of moles of hydrogen produced \[=3:3=1:1\]


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