EAMCET Medical EAMCET Medical Solved Paper-2009

  • question_answer
    The vapour of a substance effuses through a small hole at the rate of 1.3 times faster than \[S{{O}_{2}}\]gas at 1 atm pressure and 500 K. The molecular weight of the gas is

    A)  49.2                                      

    B)  37.9

    C)  41.6                                      

    D)  83.2

    Correct Answer: B

    Solution :

                     From Grahams law of diffusion \[\frac{{{r}_{x}}}{{{r}_{S{{O}_{2}}}}}=\sqrt{\frac{{{M}_{S{{O}_{2}}}}}{{{M}_{x}}}}\] \[\frac{1.3}{1}=\sqrt{\frac{64}{{{M}_{x}}}}\] \[\Rightarrow \]               \[{{M}_{x}}=\frac{64}{1.3\times 1.3}=37.86\] \[=37.9\]


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