A) It reduces ferricyanide to ferrocyanide in acid medium.
B) It oxidises lead monoxide to lead dioxide.
C) It acts as a reducing agent in the decolourisation of acidified \[\text{KMn}{{\text{O}}_{\text{4}}}\text{.}\]
D) It oxidises hydrides of chlorine and bromine to their diatomic gases.
Correct Answer: C
Solution :
\[{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}\]reduces acidified \[\text{KMn}{{\text{O}}_{4}}\]into colourless magnous salt and gets oxidised into \[{{\text{O}}_{\text{2}}}\text{.}\] \[5{{H}_{2}}{{O}_{2}}+2KMn{{O}_{4}}+3{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}\underset{\text{colourless}}{\mathop{{{K}_{2}}S{{O}_{4}}}}\,\] \[+2MnS{{O}_{4}}+8{{H}_{2}}O+5{{O}_{2}}\]
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