A) \[BaO+{{O}_{3}}\xrightarrow{{}}Ba{{O}_{2}}+{{O}_{2}}\]
B) \[PbS+4{{O}_{3}}\xrightarrow{{}}PbS{{O}_{4}}+4{{O}_{2}}\]
C) \[{{H}_{2}}{{O}_{2}}+{{O}_{3}}\xrightarrow{{}}{{H}_{2}}O+2{{O}_{2}}\]
D) \[2Hg+{{O}_{3}}\xrightarrow{{}}H{{g}_{2}}O+{{O}_{2}}\]
Correct Answer: A
Solution :
\[{{\text{O}}_{\text{3}}}\]does not react with \[\text{BaO}\text{.}\] Inspite of this, it reacts with \[\text{Ba}{{\text{O}}_{\text{2}}}\text{.}\]Here, peroxide \[\text{( }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ O }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ )}\] acts as oxidising as well as reducing agent. \[Ba{{O}_{2}}+{{O}_{3}}\xrightarrow{{}}BaO+2{{O}_{2}}\]
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