A) 2.5 s
B) 4 s
C) 1 s
D) \[\frac{10}{\sqrt{2}}s\]
Correct Answer: D
Solution :
As the velocities are same, so the persons will move according to figure. When person A will reach the position of B, they will be at closest distance but then person B will be at point C. Here the covered distances by A and B are AB (covered by A) = 10 unit along y-axis BC (covered by B) = 10 unit along y-axis Velocity in covering these distances, \[{{t}_{A}}=\frac{10}{2}=5\,unit\] \[{{t}_{B}}=\frac{10}{2}=5\,unit\] Resultant time, \[t=\sqrt{t_{A}^{2}+t_{B}^{2}}\] \[=\sqrt{{{(5)}^{2}}+{{(5)}^{2}}}\] \[=5\sqrt{2}\] \[=\frac{10}{\sqrt{2}}\text{unit}\]You need to login to perform this action.
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