A) \[10.7{}^\circ C\]
B) \[21.4{}^\circ C\]
C) \[107{}^\circ C\]
D) \[214{}^\circ C\]
Correct Answer: D
Solution :
Given, \[E=2.1V,\,r=0.05\,\Omega ,\,t=5s,\,R=0.02\Omega \] \[m=1\,g\]and \[s=0.1\,cal/g{{/}^{o}}C\] \[m\times s\times \Delta T=\frac{{{i}^{2}}Rt}{4.2}\] \[m\times s\times \Delta T=\frac{{{\left( \frac{E}{R+r} \right)}^{2}}Rt}{4.2}\] \[1\times 0.1\times \Delta T=\left( \frac{2.1\times 2.1}{0.07\times 0.07} \right)\times \frac{0.02\times 5}{4.2}\] \[\Delta \Tau =\frac{90}{0.1\times 4.2}=\frac{900}{4.2}\] \[\Delta \Tau =214{{\,}^{o}}C\]
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