A) \[1.17V\]
B) \[0.35V\]
C) \[-1.17V\]
D) \[-0.35V\]
Correct Answer: B
Solution :
EMF of the cell\[=E_{cathode}^{o}-E_{anode}^{o}\] \[=E_{F{{e}^{2+}}/Fe}^{o}-E_{Z{{n}^{2+}}/Zn}^{o}\] \[=-0.41-(-0.76)=+0.35V\]You need to login to perform this action.
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