A) 3 : 7
B) 7 : 4
C) 4 : 7
D) 7 : 5
Correct Answer: D
Solution :
\[\frac{{{I}_{\max }}}{{{I}_{\min }}}={{\left( \frac{{{a}_{1}}+{{a}_{2}}}{{{a}_{1}}-{{a}_{2}}} \right)}^{2}}\] \[\frac{{{a}_{1}}+{{a}_{2}}}{{{a}_{1}}-{{a}_{2}}}=\sqrt{\frac{36}{1}}\] \[\frac{{{a}_{1}}+{{a}_{2}}}{{{a}_{1}}-{{a}_{2}}}=6\] \[{{a}_{1}}+{{a}_{2}}=6{{a}_{1}}-6{{a}_{2}}\] \[7{{a}_{2}}=5{{a}_{1}}\] \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{7}{5}\] \[\Rightarrow \]\[{{a}_{1}}-{{a}_{2}}=7:5\]
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