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EAMCET Medical EAMCET Medical Solved Paper-2010

  • question_answer
    A short bar magnet is arranged with its North pole pointing geographical North. It is found that the horizontal component of Earths magnetic induction (BH ) is balanced by the magnetic induction of the magnet at a point which is at a distance of 20 cm from its centre. The magnetic moment of the magnet is                 (if\[{{B}_{H}}=4\times {{10}^{-5}}Wb\text{ }-{{m}^{-2}}\])

    A)                  3.2 A- m2                            

    B)                  1.6 A- m2

    C)                  6.4 A- m2                            

    D)                  0.8 A- m2

    Correct Answer: A

    Solution :

                     \[{{B}_{H}}=\frac{{{\mu }_{0}}}{4\pi }.\frac{M}{{{r}^{3}}}\]                 \[4\times {{10}^{-5}}={{10}^{-7}}\times \frac{M}{{{(20)}^{3}}{{10}^{-6}}}\]                 \[\frac{{{(20)}^{3}}\times 4\times {{10}^{-5}}\times {{10}^{-6}}}{{{10}^{-7}}}=M\]                 \[M=3.2\,A{{m}^{2}}\]


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