A) \[\frac{3h}{2\pi }\]
B) \[\frac{h}{2\pi }\]
C) \[\frac{h}{\pi }\]
D) \[\frac{3h}{\pi }\]
Correct Answer: A
Solution :
Given, distance of electron from nucleus, ie, Radius \[{{r}_{n}}=4.768\overset{\text{o}}{\mathop{\text{A}}}\,\]A Radius of first Bohrs orbit, \[r=0.53\overset{\text{o}}{\mathop{\text{A}}}\,\] \[{{r}_{n}}=r\times {{n}^{2}}\] \[4.768=0.528\times {{n}^{2}}\] \[{{n}^{2}}=9.0\] \[\therefore \] \[n=3\] Angular momentum of electron \[=\frac{nh}{2\pi }=\frac{3h}{2\pi }\]
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