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EAMCET Medical EAMCET Medical Solved Paper-2010

  • question_answer
    What is the emf of the cell for the reaction \[F{{e}^{2+}}+Zn\xrightarrow{{}}Z{{n}^{2+}}+Fe\] ? given that

    A)   \[1.17V\]                          

    B)  \[0.35V\]

    C)  \[-1.17V\]          

    D)  \[-0.35V\]

    Correct Answer: B

    Solution :

                     EMF of the cell\[=E_{cathode}^{o}-E_{anode}^{o}\] \[=E_{F{{e}^{2+}}/Fe}^{o}-E_{Z{{n}^{2+}}/Zn}^{o}\] \[=-0.41-(-0.76)=+0.35V\]


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