A) 1/2
B) 2/3
C) 1/4
D) 1/3
Correct Answer: D
Solution :
Let the weights of methane and oxygen \[=xg\] Moles of methane \[=\frac{x}{16}\] Moles of oxygen \[=\frac{x}{32}\] Mole fraction of oxygen \[\text{=}\frac{\text{moles}\,\text{of}\,\text{oxygen}}{\text{total}\,\text{number}\,\text{of}\,\text{moles}}\] \[=\frac{\frac{x}{32}}{\frac{x}{16}+\frac{x}{32}}=\frac{1}{3}\] Fraction of pressure exerted by oxygen \[=\frac{1}{3}\]You need to login to perform this action.
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