A) \[2.5\times {{10}^{15}}Hz\]
B) \[2\times {{10}^{15}}Hz\]
C) \[4.144\times {{10}^{15}}Hz\]
D) \[3\times {{10}^{16}}Hz\]
Correct Answer: B
Solution :
\[{{V}_{0}}=\frac{h}{e}(v-{{v}_{0}})\] or \[(v-{{v}_{0}})=\frac{{{V}_{0}}\times e}{h}\] \[=\frac{4.144\times 1.6\times {{10}^{-19}}}{6.63\times {{10}^{-34}}}\] \[v-1\times {{10}^{5}}={{10}^{15}}\] Frequency \[={{10}^{15}}+1\times {{10}^{15}}\] \[=2\times {{10}^{15}}Hz\]
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