EAMCET Medical EAMCET Medical Solved Paper-2010

  • question_answer
    A photon of wavelength 6630 k is incident on a totally reflecting surface. The momentum delivered by the photon is equal to

    A)                  \[6.63\times {{10}^{-27}}k{{g}^{-}}m/s\]

    B)                  \[2\times {{10}^{-27}}k{{g}^{-}}m/s\]

    C)                  \[{{10}^{-27}}k{{g}^{-}}m/s\]

    D)                  None of the above

    Correct Answer: B

    Solution :

                     \[P=n\left( \frac{E}{t} \right)\]                 \[10\,kWh=n\left[ \frac{200\,MeV}{t} \right]\]                 \[10\times {{10}^{3}}\times 60\times 60=n\times 200\times {{10}^{6}}\times 1.6\times {{10}^{-19}}\]                 \[(\because \,t=1)\]                 \[n=\frac{10\times {{10}^{3}}\times 60\times 60}{200\times {{10}^{6}}\times 1.6\times {{10}^{-19}}}\]                 \[n=\frac{36\times {{10}^{19}}}{200\times 1.6}\]                 \[n=\frac{360\times {{10}^{18}}}{200\times 1.6}\]                 \[n=1.125\times {{10}^{18}}\]                 \[n=11.25\times {{10}^{17}}\]


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