A) \[+1\]
B) \[+4\]
C) \[+2\]
D) \[+3\]
Correct Answer: C
Solution :
In \[{{[Pt\,({{C}_{2}}{{H}_{4}})C{{l}_{3}}]}^{-}}\] suppose the oxidation number of Pt is x \[x+0(-1\times 3)=-1\](\[\because \] oxidation state of\[{{C}_{2}}{{H}_{4}}\]is zero) \[x-3=-1\] \[x=+2\]You need to login to perform this action.
You will be redirected in
3 sec