A) flux density in the field
B) energy of the particle
C) charge on the particle
D) the momentum of the particle
Correct Answer: D
Solution :
The necessary centripetal force for circular path is provided by the magnetic force i.e., \[\frac{m{{\upsilon }^{2}}}{r}=q\upsilon B\] So, the radius of circular path is \[r=\frac{m\upsilon }{qB}\] Hence, the radius of circular path is directly proportional to \[m\upsilon \] i.e., momentum of particle,
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