A) 1.8 A
B) 1.5 A
C) 0.8 A
D) 0.6 A
Correct Answer: D
Solution :
Net emf of combination of cells in parallel order = emf of each cell \[=1.5V\] Net internal resistance is \[{{r}_{in}}=\frac{r}{n}=\frac{2}{4}=0.5\Omega \] external resistance \[R=2\Omega \] So, current is given by \[i=\frac{E}{R+{{r}_{in}}}=\frac{1.5}{2+0.5}\] \[=\frac{1.5}{2.5}=0.6A\]You need to login to perform this action.
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