A) \[104kcal\]
B) \[104kcal\]
C) \[10.4\text{ }kcal\]
D) \[1040\text{ }kcal\]
Correct Answer: A
Solution :
Sol. \[2{{H}_{2}}\xrightarrow{{}}4H,\] \[\Delta H=208kcal\] \[H-H\xrightarrow{{}}2H;\] \[\Delta H=\frac{208}{2}=104kcal\]You need to login to perform this action.
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