A) \[0.19{}^\circ C\]
B) \[2.3{}^\circ C\]
C) \[0.59{}^\circ C\]
D) \[1.17{}^\circ C\]
Correct Answer: D
Solution :
Here: \[h=500mg\,=9.8m/{{s}^{2}}\] \[c=4200J/k{{g}^{o}}C\] Using the relation \[mgh=mc\Delta \theta \] \[m\times 9.8\times 500=m\times 4200\times \Delta \theta \] So, \[\Delta \theta =\frac{9.8\times 500}{4200}\] \[={{1.17}^{o}}C\]You need to login to perform this action.
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