A) 4
B) 8
C) 2
D) zero
Correct Answer: A
Solution :
When source and observer are moving close to each other, then apparent frequency \[n=\left( \frac{\upsilon +{{\upsilon }_{o}}}{\upsilon -{{\upsilon }_{s}}} \right)\times n\] ...(1) Here, \[{{\upsilon }_{s}}=1m/s,\,{{\upsilon }_{0}}=1m/s,n=680Hz\] So, from equation (1) \[n=\left( \frac{340+1}{340-1} \right)680=684\] Number of beats per second \[=684-680=4\text{ }beats/sec\]You need to login to perform this action.
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