A) \[180kJ\text{ }mol{{e}^{-1}}\]
B) \[360kJ\text{ }mol{{e}^{-1}}\]
C) \[213kJ\text{ }mol{{e}^{-1}}\]
D) \[425kJ\text{ }mol{{e}^{-1}}\]
Correct Answer: D
Solution :
\[\frac{1}{2}{{H}_{2}}+\frac{1}{2}C{{l}_{2}}\xrightarrow{{}}HCl;\] \[\Delta H=-90kJ\] \[-\Delta H=\frac{1}{2}B.E.(H-H)+\frac{1}{2}B.E(Cl-Cl)\] or \[-90=\frac{1}{2}[430]+\frac{1}{2}[240]-B.E.(H-Cl)\] or \[-90=215+120-B.E.(H-Cl)\] \[B.E.(H-Cl)=215+120+90\] \[=425kJ\,mol{{e}^{-1}}\]You need to login to perform this action.
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