A) \[\frac{I{{L}^{2}}}{4{{\pi }^{2}}}\]
B) \[I\pi {{L}^{2}}\]
C) \[\frac{I{{L}^{2}}}{4\pi }\]
D) \[4\pi I{{L}^{2}}\]
Correct Answer: C
Solution :
Magnetic moment \[M=IA\] Length of wire is L \[\therefore \] \[2\pi r=L\] \[r=\frac{L}{2\pi }\] \[\therefore \] \[M=I\,\pi {{r}^{2}}\] \[=I\frac{\pi {{L}^{2}}}{4{{\pi }^{2}}}\] \[=\frac{I{{L}^{2}}}{4\pi }\]You need to login to perform this action.
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