A) 90 \[\Omega \]
B) 45 \[\Omega \]
C) 30 \[\Omega \]
D) 15 \[\Omega \]
Correct Answer: C
Solution :
Resistance of the wire \[R\propto \frac{1}{{{r}^{2}}(radius)}\] Radius of new wire is \[\frac{1}{3}rd\] of the initial wire. its resistance \[R=10{{(3)}^{2}}\] \[=10\times 9\] \[=90\Omega \] Now total resistance of all the 3 wires in parallel \[=\frac{90}{3}=30\Omega \]You need to login to perform this action.
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