A) \[\frac{2a}{3b}\]
B) \[\frac{1}{b}\]
C) \[\frac{a}{3b}\]
D) \[0\]
Correct Answer: C
Solution :
\[x=a{{t}^{2}}-b{{t}^{3}}\] Velocity \[\upsilon =\frac{dx}{dt}=2at-3b{{t}^{2}}\] Acceleration \[a=\frac{{{a}^{2}}x}{dt}=2a-6bt\] substituting acceleration \[a=0\] \[\Rightarrow \] \[2a-6\,bt=0\] \[t=\frac{2a}{6b}=\frac{a}{3b}\]You need to login to perform this action.
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