A) 90
B) 100
C) 200
D) 5
Correct Answer: B
Solution :
Equation of wave \[y=20\sin \pi (0.02x-2t\] comparing it with standard equation \[y=A\sin (kx-\omega t)\] we get \[k=0.02\pi \] Wavelength \[\lambda =\frac{2\pi }{k}=\frac{2\pi }{0.02\pi }=100cm\].You need to login to perform this action.
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