A) 1 mg
B) 3.6 kg
C) 3.3 kg
D) 1kg
Correct Answer: B
Solution :
Power consumed \[=V\times q\] \[\therefore \] \[{{V}_{q}}=100\times 1000\times 3600J\] \[{{V}_{q}}=3.6\times {{10}^{8}}J\] \[q=\frac{3.6\times {{10}^{8}}}{V}=\frac{3.6\times {{10}^{8}}}{33}C\] Now \[m=zq\] \[=\frac{0.33\times {{10}^{-6}}\times 3.6\times {{10}^{8}}}{33}=3.6kg\]You need to login to perform this action.
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