A) 50 J
B) 30 J
C) 20J
D) 10J
Correct Answer: C
Solution :
We know that velocity at the top is \[\sqrt{gr}\]and that at the bottom is \[\sqrt{5gr}\]gr Now difference in \[K.E.=\frac{1}{2}m[5gr-gr]=2mgr\] \[=2\times 1\times 10\times 1=20J\]You need to login to perform this action.
You will be redirected in
3 sec