A) in two
B) in all
C) in all leaving one
D) none of these
Correct Answer: A
Solution :
\[HF\] and \[C{{H}_{3}}OH\]shows intermolecular hydrogen bonding. Hydrogen bonding is present between a highly electronegative element and hydrogen. Hence, \[C{{H}_{4}}\]and \[{{N}_{2}}{{O}_{4}}\]cant show hydrogen bonding.You need to login to perform this action.
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