A) \[\frac{r}{3}\]
B) \[\frac{r}{2}\]
C) \[\frac{2}{3}r\]
D) 2r
Correct Answer: B
Solution :
Body will be detached if \[\frac{m{{\upsilon }^{2}}}{r}=mg\,\,\cos \theta \] ??(i) As \[{{\upsilon }^{2}}-{{0}^{2}}=2gd\] \[\upsilon =\sqrt{2gd}\] and \[\cos \theta =\frac{h}{r}\] So, from equation (i), \[\frac{m\times 2gd}{r}=mg\frac{h}{r}\] or \[h=2d\] or \[h=2(r-h)\] i.e., \[h=(2/3)r\]You need to login to perform this action.
You will be redirected in
3 sec