A) \[9.30\]
B) \[7.30\]
C) \[10.30\]
D) \[8.30\]
Correct Answer: D
Solution :
Cone. of KCN = cone. of HCN \[=\frac{2.5}{500/1000}\] \[=5M\] \[\therefore \] \[\log \frac{[KCN]}{[HCN]}=\log \frac{5}{5}=0\] Now, from Hendersons equation, \[pH{{=}_{p}}{{K}_{a}}+\log \frac{[salt]}{[acid]}\] \[=9.30+0=9.30\]You need to login to perform this action.
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