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Haryana PMT Haryana PMT Solved Paper-2005

  • question_answer
    Osmotic pressure of a solution is 0.0821 atm at a temperature of 300K. The concentration in .mole per litre will be:

    A)  \[0.33\]                              

    B)  \[0.066\]

    C)  \[0.3\times {{10}^{-2}}\]             

    D)  \[3\]

    Correct Answer: D

    Solution :

                    \[\pi .\,\,V=n.RT\]or    \[\frac{n}{V}=\frac{\pi }{RT}=\frac{0.0821}{300\times 0.0821}\]     \[=0.3\times {{10}^{-2}}mole/litre\]


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