A) tan \[\phi \] = 2tan \[\text{ }\!\!\theta\!\!\text{ }\]
B) tan \[\phi \] = 3tan \[\text{ }\!\!\theta\!\!\text{ }\]
C) tan \[\phi \] = tan \[\text{ }\!\!\theta\!\!\text{ }\]
D) tan \[\text{ }\!\!\theta\!\!\text{ }\] = 3tan \[\phi \]
Correct Answer: D
Solution :
Here, \[mg(\sin \phi +\mu \,cos\phi )\] \[=2mg(\sin \phi -\mu \cos \phi )\] \[\Rightarrow \] \[\tan \phi =3\mu \] As \[\mu =\tan \theta \] So, \[\tan \phi =3tan\theta \]You need to login to perform this action.
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