A) \[\frac{1}{10\lambda }\]
B) \[\frac{1}{11\lambda }\]
C) \[\frac{1}{10\lambda }\]
D) \[\frac{1}{9\lambda }\]
Correct Answer: B
Solution :
\[{{N}_{A}}=No{{e}^{-10\lambda t}}\] and \[{{N}_{B}}=No{{e}^{-\lambda t}}\] \[\Rightarrow \] \[\frac{{{N}_{A}}}{{{N}_{B}}}=\frac{1}{e}={{e}^{(-10\lambda +\lambda )t}}\] or \[9\lambda t=1\] \[\therefore \] \[t=\frac{1}{9\lambda }\]You need to login to perform this action.
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