A) less than w
B) equal to w
C) equal to 2w
D) infinitely large
Correct Answer: D
Solution :
For equilibrium of body \[mg=2T\,\cos \theta \] \[T=\frac{mg}{2cos\theta }\] For the string to be horizontal \[\theta \to {{90}^{o}}\] \[\therefore \] \[T=\frac{mg}{2\cos {{90}^{o}}}\] \[\Rightarrow \]\[T\to \infty \]You need to login to perform this action.
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