A) \[[ML{{T}^{-1}}A]\]
B) \[[{{M}^{2}}L{{T}^{2}}{{A}^{-1}}]\]
C) \[[M{{T}^{-2}}{{A}^{-1}}]\]
D) none of these
Correct Answer: C
Solution :
\[F=q\overrightarrow{v}\times \overrightarrow{B}\] or \[F=\,q\,\,v\,\,B\,\,\sin \theta \] \[[B]=\left[ \frac{F}{qv} \right]=\frac{[ML{{T}^{-1}}]}{[AT][L{{T}^{-1}}]}\] \[=[M{{T}^{-2}}{{A}^{-1}}]\]You need to login to perform this action.
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