A) \[\frac{1}{3}\]
B) \[\frac{1}{3}\]
C) 3
D) 2
Correct Answer: A
Solution :
Specific heat of water \[=4200\text{ }J/kg\text{ }-\text{ }K\] Specific latent heat of fusion \[=3.36\times {{10}^{5}}j/KG\] Specific latent heat of vaporisation \[=22.68\times {{10}^{5}}J/kg\] \[=X\times {{10}^{-3}}\times 22.68\times {{10}^{5}}\] \[=Y+{{10}^{-3}}\times 3.36\times {{10}^{5}}+Y\times {{10}^{-3}}\] \[\times 4200\times 100\] \[\therefore \] \[\frac{X}{Y}=\frac{7.56}{22.68}=\frac{1}{3}\]You need to login to perform this action.
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