A) 2km/s
B) 3km/s
C) 4km/s
D) 5km/s
Correct Answer: B
Solution :
Let the shift in frequency \[=\Delta n\] \[\Delta n=100\times {{10}^{3}}Hz\] v =- relative speed Then, \[\frac{\Delta n}{n}=2\frac{v}{c}\] \[v=\frac{\Delta n}{2n}c\] \[=\frac{100\times {{10}^{3}}\times 3\times {{10}^{8}}}{2\times 5000\times {{10}^{6}}}\] \[=3000m/s\] \[=3km/s\]You need to login to perform this action.
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